1988 All-Japan Championship
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The 1988 All-Japan Championship was the 56th edition of the national ice hockey championship in Japan. It was contested by six teams, and Kokudo Keikaku won the championship.
Preliminary round
- First round
- 12/24: Jujo Seishi Kushiro - Furukawa Nikko 7:1 (2:0, 2:0, 3:1)
- Second round
- 12/25: Jujo Seishi Kushiro - Seibu Tokyo 4:3 OT (2:0, 0:1, 1:2, 1:0)
Semifinals
- 12/27: Oji Seishi - Jujo 6:2 (1:1, 5:0, 0:1)
- 12/27: Yukijrushi - Kokudo Keikaku 5:3 (1:1, 2:0, 2:2)
- 12/28: Kokudo Keikaku - Jujo 7:2 (5:1, 0:0, 2:1)
- 12/28: Oji Seishi - Yukijrushi 6:2 (2:1, 0:0, 4:1)
- 12/30: Yukijrushi - Jujo 5:3 (2:0, 1:0, 2:3)
- 12/30: Kokudo Keikaku - Oji Seishi 6:4 (0:2, 6:0, 0:2)
Team | GP | W | T | L | GF | GA | Pts | |
---|---|---|---|---|---|---|---|---|
1. | Oji Seishi Tomakomai | 3 | 2 | 0 | 1 | 16 | 10 | 4 |
2. | Kokudo Keikaku | 3 | 2 | 0 | 1 | 16 | 11 | 4 |
3. | Yukijrushi Sapporo | 3 | 2 | 0 | 1 | 12 | 12 | 4 |
4. | Jujo Seishi Kushiro | 3 | 0 | 0 | 3 | 7 | 18 | 0 |
Final round
- 3rd place game
- 1/2: Yukijrushi Sapporo - Jujo Seishi Kushiro 2:1 (1:0, 0:1, 1:0)
- Final
- 1/2: Kokudo Keikaku - Oji Seishi Tomakomai 4:3 OT (3:2, 0:1, 0:0, 1:0)
Sources
- Yomiuri Shimbun